Question

Арман идет шагом со скоростью 4 км/ч и бежит со скоростью 6 км/ч. Расстояние от дома до школы он пробегает на 3 мин 45 сек быстрее, чем идет шагом. Найдите расстояние от дома до школы.

Answer 1

Ответ:

4×6=24  

45÷3=15  

15+24=39    

Answer 2

Problem Analysis

We are given that Arman walks at a speed of 4 km/h and runs at a speed of 6 km/h. The distance from home to school is covered by Arman in 3 minutes and 45 seconds less when he runs compared to when he walks. We need to find the distance from home to school.

Solution

Let's assume the distance from home to school is d kilometers.

When Arman walks, he covers the distance at a speed of 4 km/h. The time taken to cover the distance is given by:

Time taken to walk = Distance / Speed = d / 4

When Arman runs, he covers the same distance at a speed of 6 km/h. The time taken to cover the distance is given by:

Time taken to run = Distance / Speed = d / 6

According to the problem, the time taken to run is 3 minutes and 45 seconds less than the time taken to walk. We can convert this time difference to hours:

3 minutes and 45 seconds = 3/60 + 45/3600 = 0.0625 hours

So, we have the equation:

Time taken to walk - Time taken to run = 0.0625

Substituting the expressions for time taken to walk and run, we get:

(d / 4) - (d / 6) = 0.0625

Simplifying the equation:

(3d - 2d) / 12 = 0.0625

d / 12 = 0.0625

d = 0.0625 * 12

d = 0.75 kilometers

Therefore, the distance from home to school is 0.75 kilometers.

Answer

The distance from home to school is 0.75 kilometers.