Question

Домашняя работа №1 Одна труба наполняет бассейн за 3 дня, а вторая - за 6 дней. За сколько дней они наполнят бассейн вместе? №2 Одна труба наполняет бассейн за 20 часов, а вторая - за 60 часов. За сколько часов они наполнят бассейн вместе?

Answer 1

Пошаговое объяснение:

1. 6*3=18 или

6+3=9

2.60:20=3 либо

60-20=40

Answer 2

Problem 1: Filling the Pool

To solve this problem, we need to determine how long it will take for two pipes to fill a pool together.

Let's consider the information given: - Pipe 1 can fill the pool in 3 days. - Pipe 2 can fill the pool in 6 days.

To find out how long it will take for both pipes to fill the pool together, we can use the concept of "work done." The work done by each pipe is inversely proportional to the time it takes to fill the pool.

Let's assume that the pool has a capacity of 1 unit (you can consider it as 1 pool).

The work done by Pipe 1 in 1 day is 1/3 (since it takes 3 days to fill the pool). The work done by Pipe 2 in 1 day is 1/6 (since it takes 6 days to fill the pool).

When both pipes are working together, their work is additive. So, the work done by both pipes in 1 day is (1/3) + (1/6) = 1/2.

To find out how long it will take for both pipes to fill the pool together, we need to calculate the time it takes for them to do a combined work of 1 unit.

Let's denote the time it takes for both pipes to fill the pool together as 't'.

The equation can be set up as follows:

(1/3)t + (1/6)t = 1

Simplifying the equation:

(2/6)t + (1/6)t = 1

(3/6)t = 1

t = 6/3

t = 2

Therefore, it will take both pipes 2 days to fill the pool together.

Answer: The two pipes will fill the pool together in 2 days.

Problem 2: Filling the Pool

To solve this problem, we need to determine how long it will take for two pipes to fill a pool together.

Let's consider the information given: - Pipe 1 can fill the pool in 20 hours. - Pipe 2 can fill the pool in 60 hours.

To find out how long it will take for both pipes to fill the pool together, we can use the concept of "work done." The work done by each pipe is inversely proportional to the time it takes to fill the pool.

Let's assume that the pool has a capacity of 1 unit (you can consider it as 1 pool).

The work done by Pipe 1 in 1 hour is 1/20 (since it takes 20 hours to fill the pool). The work done by Pipe 2 in 1 hour is 1/60 (since it takes 60 hours to fill the pool).

When both pipes are working together, their work is additive. So, the work done by both pipes in 1 hour is (1/20) + (1/60) = 1/15.

To find out how long it will take for both pipes to fill the pool together, we need to calculate the time it takes for them to do a combined work of 1 unit.

Let's denote the time it takes for both pipes to fill the pool together as 't'.

The equation can be set up as follows:

(1/20)t + (1/60)t = 1

Simplifying the equation:

(3/60)t + (1/60)t = 1

(4/60)t = 1

t = 60/4

t = 15

Therefore, it will take both pipes 15 hours to fill the pool together.

Answer: The two pipes will fill the pool together in 15 hours.