Question

Сума двох чисел дорівнює 40. знайди ці числа , якщо одне з них у 4 рази менше за інше.

Answer 1

Ответ:

8 и 32

Пошаговое объяснение:

Пусть х меньшее число, тогда 4х большее

Их сумма = 40

х + 4х = 40

5х = 40

х = 40/5

х = 8 - меньшее число

8*4 = 32 - большее число

Answer 2

Ответ:

Пошаговое объяснение:

Меньшее число равно х

Большее число равно 4х

Составим уравнение

х+4х=40

5х=40

Х=40:5

Х=8 меньшее число

8×4=32 большее число

Answer 3

Problem Analysis

We are given that the sum of two numbers is 40, and one of the numbers is 4 times smaller than the other. We need to find these two numbers.

Solution

Let's assume the larger number is x and the smaller number is y. We can set up two equations based on the given information:

1. The sum of the two numbers is 40: x + y = 40. 2. One of the numbers is 4 times smaller than the other: x = 4y.

We can solve this system of equations to find the values of x and y.

Solving the System of Equations

To solve the system of equations, we can substitute the value of x from the second equation into the first equation:

4y + y = 40

Simplifying the equation:

5y = 40

Dividing both sides of the equation by 5:

y = 8

Now, we can substitute the value of y back into the second equation to find the value of x:

x = 4 * 8 = 32

Therefore, the two numbers are 32 and 8.

Answer

The two numbers are 32 and 8.