Question

При каком значении а уравнение (а-6)х=28 имеет корень равный 7 , не имеет корней и (а-2)х=45 имеет корень равный,5 не имеет корней.СРОЧНО ДАМ 200 БАЛЛОВ!!!!!!!!! СРОЧНО!!!

Answer 1

Ответ:

1)имеет корень 7 когда х=28,не имеет корней при х=0

2)иммет корень 5 когда х=15,не имееь корней при х=0

Пошаговое объяснение:

Answer 2

Ответ:

Пошаговое объяснение:

а)

(а-6)х=28

х=7

(а-6)*7=28

а-6=4

а=4+6=10.

Не имеет корней:

а-6=0

а=6.

б)

(а-2)х=45

х=5

а-2=45/5=9

а=9+2=11

Не имеет корней:

а-2=0

а=2.

Answer 3

Solving the Equation for Different Values of a

To find the values of a for which the equation (a-6)x=28 has a root equal to 7, no roots, and the equation (a-2)x=45 has a root equal to 5 and no roots, we can use the concept of discriminant in quadratic equations.

1. (a-6)x=28 has a root equal to 7: - For the equation to have a root, the discriminant should be greater than or equal to 0. - The discriminant, D, for the equation ax^2 + bx + c = 0 is given by D = b^2 - 4ac. - In this case, the discriminant for the equation (a-6)x=28 is D = 0^2 - 4(a-6)(-28) = 112a - 672. - For the equation to have a root equal to 7, the discriminant should be greater than or equal to 0: 112a - 672 ≥ 0.

2. (a-6)x=28 has no roots: - For the equation to have no roots, the discriminant should be less than 0: 112a - 672 < 0.

3. (a-2)x=45 has a root equal to 5: - Similarly, for the equation (a-2)x=45, the discriminant is D = 0^2 - 4(a-2)(-45) = 180 - 4a. - For the equation to have a root equal to 5, the discriminant should be greater than or equal to 0: 180 - 4a ≥ 0.

4. (a-2)x=45 has no roots: - For the equation to have no roots, the discriminant should be less than 0: 180 - 4a < 0.

Calculating the Values of a

Now, let's calculate the values of a based on the conditions derived above.

1. For (a-6)x=28 to have a root equal to 7: - 112a - 672 ≥ 0 - Solving for a: a ≥ 6

2. For (a-6)x=28 to have no roots: - 112a - 672 < 0 - Solving for a: a < 6

3. For (a-2)x=45 to have a root equal to 5: - 180 - 4a ≥ 0 - Solving for a: a ≤ 45

4. For (a-2)x=45 to have no roots: - 180 - 4a < 0 - Solving for a: a > 45

Conclusion

Based on the calculations, the values of a for the given conditions are as follows: - (a-6)x=28 has a root equal to 7 when a ≥ 6. - (a-6)x=28 has no roots when a < 6. - (a-2)x=45 has a root equal to 5 when a ≤ 45. - (a-2)x=45 has no roots when a > 45.

Therefore, the values of a for the given conditions are: - (a-6)x=28 has a root equal to 7 when a ≥ 6. - (a-6)x=28 has no roots when a < 6. - (a-2)x=45 has a root equal to 5 when a ≤ 45. - (a-2)x=45 has no roots when a > 45.