Question

Ученик выполняет работу за 7 дней. Работая вместе мастер и ученик работу закончили за 28/ 11 дней. Сколько выполнял бы данную работу мастер. ПОМОГИ​

Answer 1

Ответ:

1)28:7=4

ответ:через 4 Мейстер закончит работу

Answer 2

Ответ: 4часа

Пошаговое объяснение:

если мастер, работая один, может выполнить всю работу за х дней, а объем всей работы 1, производительность мастера и  ученика соответственно 1/х и 1/7,

то 1/х+1/7=1/(28/11);

1/х+1/7=11/28⇒28+4х=11х; 28=7х; х=4

Мастер выполнил бы данную работу за 4 часа.

Answer 3

Problem Analysis

We are given that a student completes a task in 7 days, and when working together with a master, they complete the task in 28/11 days. We need to determine how long the master would take to complete the task alone.

Solution

Let's assume that the master takes x days to complete the task alone.

From the given information, we can set up the following equation based on the work rates of the student and the master:

1/7 + 1/x = 1/(28/11)

To solve for x, we can simplify the equation:

1/7 + 1/x = 11/28

To eliminate the fractions, we can multiply both sides of the equation by the least common denominator (LCD), which is 28x:

4x + 28 = 11x

Simplifying further:

28 = 7x

Dividing both sides by 7:

x = 4

Therefore, the master would take 4 days to complete the task alone.

Answer

The master would take 4 days to complete the task alone.