Question

(2x+1)^2-(2x-1)^2=16

Answer 1

$(2x+1)^2-(2x-1)^2=16\\2\cdot4x=16\\8x=16\\x=16:8\\x=2$

Answer 2

Для начала, раскроем скобки:

(2x+1)^2 = (2x+1)(2x+1) = 4x^2 + 2x + 2x + 1 = 4x^2 + 4x + 1

(2x-1)^2 = (2x-1)(2x-1) = 4x^2 -