Question

в первой вазе лежало в 3 раза больше конфет чем в третьей, во второй вазе на 5 конфет больше чем в третьей. Сколько конфет лежало в первой вазе, если их в этих вазах было всего 165 конфет срочно помогите нужено полное решение пожалуйста ​

Answer 1

Відповідь:

Покрокове пояснення:

пусть в третей вазе х конфет тогда в первой вазе 3х конфет, а во второй будет х+5 составим и решим уравнение

х+х+5+3х=165

5х=160

х=32 конфет в 3 вазе

32*3=96 конфет в первой вазе

32+5= 37 конфет во второй вазе

Answer 2

Ответ:

Примем количество конфет в третьей вазе за x. Тогда:

1 ваза- 3x

2 ваза- x+5

3 ваза- x

Всего- 165

Чтобы найти количество конфет, составим уравнение и найдем x:

3x + x + x+5=165

5x+5=165

5x =165-5

5x=160

x=32

32 конфеты в третьей вазе. Значит в первой вазе:

32*3=96(конфет)

Ответ: в первой вазе 96 конфет.

Answer 3

Problem Analysis

To solve this problem, we need to find the number of candies in the first vase, given that there were a total of 165 candies in the three vases. We know that the first vase had three times as many candies as the third vase, and the second vase had 5 more candies than the third vase.

Solution

Let's denote: - The number of candies in the first vase as x - The number of candies in the third vase as y

We can then form the following equations based on the given information: 1. x = 3y (The first vase had three times as many candies as the third vase) 2. x - y = 5 (The second vase had 5 more candies than the third vase) 3. x + y + (x - y) = 165 (The total number of candies in the three vases is 165)

Calculations

Using the equations above, we can solve for the values of x and y.

From equation 1, we have x = 3y. From equation 2, we have x - y = 5, which can be rewritten as x = y + 5.

Substituting the value of x from equation 1 into equation 3: 3y + y + (y + 5) = 165 5y + 5 = 165 5y = 160 y = 32

Substituting the value of y back into equation 1: x = 3 * 32 x = 96

Answer

Therefore, there were 96 candies in the first vase.

Final Note

I hope this solution helps! If you have any further questions or need additional assistance, feel free to ask!