Question

В коробке лежат 10 карточек, пронумерованных числами от 1 до 10. Какова вероятность того, что на вынутой карточке будет записано: 1) число, кратное 3, меньше 5 ,число сумма цифр которого равно 6

Answer 1

Ответ:

Пошаговое объяснение:

1) так как из n=10 карточек всего m=3 карточки имеют номера, кратные 3 (3, 6 и 9), и при этом выбор любой карточки равновероятен, то искомая вероятность p=m/n=3/10=0,3.

2) так как из n=10 карточек всего m=4 карточки имеют номера, меньшие 5, и прит этом выбор любой карточки равновероятен, то искомая вероятность p=m/n=4/10=0,4.

3) Сумма цифр равна 6 только у m=1 карточки из n=10 карточек - карточки с числом 6. И так как выбор любой карточки равновероятен, то искомая вероятность p=m/n=1/10=0,1.

Answer 2

Probability of drawing a card that is a multiple of 3, less than 5, and has a digit sum of 6

To calculate the probability of drawing a card that meets all three conditions (being a multiple of 3, less than 5, and having a digit sum of 6), we need to determine the number of cards that satisfy these conditions and divide it by the total number of cards in the box.

Let's break down each condition and calculate the probability step by step:

1. Being a multiple of 3: Out of the 10 cards in the box, we need to identify the cards that are multiples of 3. From the given information, we know that the cards are numbered from 1 to 10. The multiples of 3 in this range are 3, 6, and 9. Therefore, there are 3 cards that are multiples of 3.

2. Being less than 5: We need to identify the cards that are less than 5. From the given information, we know that the cards are numbered from 1 to 10. The cards that are less than 5 are 1, 2, 3, and 4. Therefore, there are 4 cards that are less than 5.

3. Having a digit sum of 6: We need to identify the cards whose digits add up to 6. From the given information, we don't have specific details about the cards' numbers. Therefore, we need to manually check each card to see if its digits add up to 6. The cards that satisfy this condition are 3 and 6.

Now, let's calculate the probability by dividing the number of cards that meet all three conditions by the total number of cards:

Number of cards that meet all three conditions: 1 (card number 3)

Total number of cards in the box: 10

Probability = Number of favorable outcomes / Total number of possible outcomes

Probability = 1 / 10

Therefore, the probability of drawing a card that is a multiple of 3, less than 5, and has a digit sum of 6 is 1/10.