Question

3) В первой бочке было в 4 раза больше воды, чем во второй. Когда из первой бочки отлили во вторую 3,9 литра, то в обоих бочках стало поровну. Сколько воды было в каждой бочке первоначально? Пж дам 35​

Answer 1

Ответ:

Пошаговое объяснение:

Пусть во второй бочке - х л воды, тогда в первой 4х л, когда из первой бочки отлили во вторую 3,9 литра, то в ней стало 4х- 3,9 л, а во второй стало х + 3,9л Составим уравнение:

4х - 3,9= х+3,9

4х - х= 3,9 + 3,9

3х= 7,8

х= 7,8 : 3

х= 2,6 л было во второй бочке первоначально

4х = 4 * 2,6= 10,4 л было в первой бочке первоначально

Answer 2

Problem Analysis

We are given two barrels, and the first barrel initially contains four times more water than the second barrel. After pouring 3.9 liters of water from the first barrel into the second barrel, the water becomes evenly distributed between the two barrels. We need to determine the initial amount of water in each barrel.

Solution

Let's assume that the initial amount of water in the second barrel is x liters. According to the problem, the first barrel initially contains four times more water than the second barrel, so the initial amount of water in the first barrel is 4x liters.

When 3.9 liters of water is poured from the first barrel into the second barrel, the amount of water in both barrels becomes equal. Therefore, we can set up the following equation:

4x - 3.9 = x + 3.9

Simplifying the equation, we get:

4x - x = 3.9 + 3.9

Simplifying further:

3x = 7.8

Dividing both sides of the equation by 3:

x = 2.6

So, the initial amount of water in the second barrel is 2.6 liters, and the initial amount of water in the first barrel is four times that amount, which is 4 * 2.6 = 10.4 liters.

Therefore, initially, there were 10.4 liters of water in the first barrel and 2.6 liters of water in the second barrel.

Please let me know if I can help you with anything else.