Question

найдите все натуральные значения, при которых: обе дроби а/10 и 15/а будут неправильными, а дробь а/13- правильной​

Answer 1

У неправильной дроби числитель больше знаменателя или равен ему.

10 ≤ a ≤ 15

Дробь а/13 будет правильной, если а < 13

Ответ: при а = {10, 11, 12}.

Answer 2

Finding the Natural Values for the Fractions

To find the natural values for which both fractions a/10 and 15/a are improper, while the fraction a/13 is proper, we need to consider the conditions for improper and proper fractions.

An improper fraction is a fraction where the numerator is greater than or equal to the denominator, while a proper fraction has a numerator that is less than the denominator.

Let's analyze each fraction separately:

Fraction a/10: For this fraction to be improper, the numerator a must be greater than or equal to 10.

Fraction 15/a: For this fraction to be improper, the denominator a must be greater than or equal to 15.

Fraction a/13: For this fraction to be proper, the numerator a must be less than 13.

To find the natural values that satisfy these conditions, we can start by considering the smallest possible values for a and then incrementally increase it while checking the conditions.

Let's go through the values step by step:

1. For a = 10, the fraction a/10 is proper (10/10 = 1), and the fraction 15/a is improper (15/10 = 1.5). 2. For a = 11, the fraction a/10 is improper (11/10 = 1.1), and the fraction 15/a is proper (15/11 ≈ 1.3636). 3. For a = 12, the fraction a/10 is improper (12/10 = 1.2), and the fraction 15/a is proper (15/12 = 1.25). 4. For a = 13, the fraction a/10 is improper (13/10 = 1.3), and the fraction 15/a is proper (15/13 ≈ 1.1538).

Based on the analysis above, we can conclude that there are no natural values for a that satisfy the conditions where both fractions a/10 and 15/a are improper, while the fraction a/13 is proper.

Please let me know if you need any further clarification or assistance!