Question

Три комбайнери за день намолотили 180т пшениці. Перший комбайнер намолотив 5/18 усієї пшениці другий 2/5 усієї пшениці скільки тонн пшениці намолотив третій комбайнер?

Answer 1

Ответ:

58 тонн намолотил третий комбайнер

Пошаговое объяснение:

1. 180 * 5/18 = 50 (т) намолотил первый комбайнер

2. 180 * 2/5 = 72 (т) намолотил второй комбайнер

3. 180 - (50 + 72) = 180 - 122 = 58 (т) намолотил третий комбайнер

Answer 2

Ответ:

58т

Пошаговое объяснение:

180*5\18=5*10=50т - 1 комбайнер

180*2\5=36*2=72т - 2 комбайнер

180-(50+72)=58т - 3 комбайнер

Answer 3

Problem Analysis

We are given that three combine harvesters harvested a total of 180 tons of wheat. The first combine harvester harvested 5/18 of the total wheat, and the second combine harvester harvested 2/5 of the total wheat. We need to determine how many tons of wheat the third combine harvester harvested.

Solution

Let's denote the amount of wheat harvested by the third combine harvester as x.

According to the given information: - The first combine harvester harvested 5/18 of the total wheat. - The second combine harvester harvested 2/5 of the total wheat. - The third combine harvester harvested x tons of wheat.

We can set up the following equation to represent the total amount of wheat harvested: (5/18) + (2/5) + x = 180

To solve for x, we need to simplify the equation and isolate x on one side: (5/18) + (2/5) + x = 180 Multiplying both sides of the equation by 90 to eliminate the denominators: 5(5) + 2(18) + 90x = 90(180) 25 + 36 + 90x = 16200 61 + 90x = 16200 90x = 16139 x = 16139/90 x ≈ 179.32

Therefore, the third combine harvester harvested approximately 179.32 tons of wheat.

Answer

The third combine harvester harvested approximately 179.32 tons of wheat.