Question

(x+y) у третьому степені. забыла как делать, помогите пожалуйста ​

Answer 1

Ответ:

(х+у)³=х³+3х²у+3ху²+у³

Пошаговое объяснение:

Answer 2

Solving (x+y) to the Third Power

To solve the expression (x+y) to the third power, you can use the formula for expanding a binomial raised to a power. In this case, you would use the binomial theorem to expand (x+y)^3.

The binomial theorem states that for any positive integer n:

(x + y)^n = C(n,0)x^n*y^0 + C(n,1)x^(n-1)*y^1 + C(n,2)x^(n-2)*y^2 + ... + C(n,n-1)x^1*y^(n-1) + C(n,n)x^0*y^n

Where C(n, k) represents the binomial coefficient, which is calculated as C(n, k) = n! / (k! * (n-k)!)

Let's calculate (x+y)^3 using the binomial theorem:

(x+y)^3 = C(3,0)x^3*y^0 + C(3,1)x^2*y^1 + C(3,2)x^1*y^2 + C(3,3)x^0*y^3

Now, let's calculate the binomial coefficients and simplify the expression.

(x+y)^3 = 1*x^3*1 + 3*x^2*y + 3*x*y^2 + 1*y^3

So, the expanded form of (x+y)^3 is:

x^3 + 3x^2y + 3xy^2 + y^3

This is the result of raising the binomial (x+y) to the third power.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.