Question

Кот Базилио, Лиса Алиса и Буратино пришли в Страну Дураков на Поле Чудес, чтобы закопать золотые монеты. Сначала Базилио закопал в ряд все свои монеты по одной. Затем между каждыми двумя закопанными монетами Алиса закопала все свои монеты по одной. Затем ровно все то же самое повторил Буратино. Сколько монет было у Базилио в начале, если Буратино закопал 20 монет? Ответ обоснуйте.

Answer 1

Ответ:

Пошаговое объяснение:

У Базилио 80 монет потому-что количество монет удваивается с 1 участником

20*2=40

40*2=80

Answer 2

Problem Analysis

In this problem, we are given that Cat Basilio, Fox Alice, and Buratino came to the Land of Fools to bury gold coins in the Field of Wonders. Basilio buried all his coins in a row, Alice buried her coins one by one between each pair of Basilio's coins, and Buratino repeated the same process. We are asked to determine how many coins Basilio had at the beginning if Buratino buried 20 coins.

Solution

Let's assume that Basilio had x coins at the beginning. Alice buried her coins one by one between each pair of Basilio's coins, so she buried x-1 coins. Similarly, Buratino repeated the same process, so he buried x-2 coins.

According to the problem, Buratino buried a total of 20 coins. Therefore, we can set up the equation:

x - 2 = 20

Solving this equation will give us the value of x, which represents the number of coins Basilio had at the beginning.

Calculation

Let's solve the equation:

x - 2 = 20

Adding 2 to both sides of the equation:

x = 20 + 2

x = 22

Therefore, Basilio had 22 coins at the beginning.

Conclusion

Based on the given information, if Buratino buried 20 coins, then Basilio had 22 coins at the beginning.