Question

Розвьжить рівнняня1/2х-4=3/8(х+8) умоляю помгите

Answer 1

$\frac{1}{2x-4} = \frac{3}{8(x+8)}$

Використовуємо властивість пропорції: добуток крайніх членів дорівеює добутку середних членів

3(2х-4)=1×8(х+8)

3×2х-4×3=8х+8×8

6х-12=8х+64

6х-8х-12=64

-2х-12=64

-2х=64+12

-2х=76

х=-38

Answer 2

I can help you solve this equation. First, let me rewrite it in a clearer way:

$$\frac{1}{2}x - 4 = \frac{3}{8}(x + 8)$$

To solve for $x$, we need to isolate it on one side of the equation. We can do this by following these steps:

- Multiply both sides by 8 to clear the fractions. This gives us:

$$4x - 32 = 3(x + 8)$$

- Expand the brackets on the right side by distributing 3. This gives us:

$$4x - 32 = 3x + 24$$

- Subtract 3x from both sides to get all the x terms on the left side. This gives us:

$$x - 32 = 24$$

- Add 32 to both sides to get all the constant terms on the right side. This gives us:

$$x = 56$$

Therefore, the solution is $x = 56$. You can check this by plugging it back into the original equation and verifying that both sides are equal. I hope this helps you understand how to solve equations like this.Ответь+подробно.++Розвьжить+рівнняня1/2х-4=3/8(х+8)+умоляю+помгите+