Question

в одном ящике было в 3 раза больше апельсинов, чем в другом. после того как из ящика взяли 20 апельсинов, а во второй положили 14, апельсинов в ящиках стало поровну. сколько апельсинов было в каждом ящике первоначально?​

Answer 1

Ответ:

в одном-17, в другом-51

Пошаговое объяснение:

возьмем за х меньший ящик.тогда второй будет- 3*х

3х-20=х+14

переносим все в одну сторону

3х-х=14+20

2х=34

х=17 .

Теперь просто умножаем х на 3:

17*3=51

Answer 2

Solving the Problem

To solve this problem, we can use algebraic equations to represent the given information and then solve for the unknown quantities.

Let's denote: - the initial number of oranges in the first box as x, - the initial number of oranges in the second box as y.

We are given the following information: 1. There were 3 times as many oranges in the first box as in the second box: x = 3y. 2. After taking 20 oranges from the first box and putting 14 oranges into the second box, the number of oranges in the two boxes became equal: (x - 20) = (y + 14).

We can now solve these equations to find the initial number of oranges in each box.

Calculating the Initial Number of Oranges

Using the given information, we can solve for the initial number of oranges in each box:

From the first piece of information, we have x = 3y.

From the second piece of information, we have (x - 20) = (y + 14).

Substituting the value of x from the first equation into the second equation, we get: 3y - 20 = y + 14.

Solving for y: 3y - y = 14 + 20 2y = 34 y = 17.

Substituting the value of y back into the first equation, we get: x = 3 * 17 x = 51.

So, the initial number of oranges in the first box was 51, and the initial number of oranges in the second box was 17.

Therefore, initially, there were 51 oranges in the first box and 17 oranges in the second box.

This information is based on the mathematical calculations and the given problem statement.