Question

Срочно даю 80баллов В первой цистерне было 4 раза больше молока,чем во второй.Когда из первой цистерны отлили 137 л молока ,а во вторую налили 48 л,то воды в первой цистерне молока стало в два раза меньше,чем во второй.Сколько литров молока было в каждой цестерне первоначально?

Answer 1

Ответ:

184 л,  46 л.

Пошаговое объяснение:

В первой цистерне 4х л молока, во второй х л молока.

(х+48)/(4х-137)=2

х+48=2(4х-137)

х+48=8х-274

322=7х

х=46

В первой цистерне было 4*46=184 л, во второй 46 л.

Answer 2

Я могу помочь вам с решением задачи по математике.

Пусть $x$ - количество литров молока в первой цистерне, а $y$ - во второй. Тогда по условию задачи имеем следующие уравнения:

$$ \begin{cases} x = 4y \\ x - 137 = 2(y + 48) \end{cases} $$

Решая систему, получаем:

$$ \begin{cases} x = 4y \\ 4y - 137 = 2y + 96 \end{cases} $$

$$ \begin{cases} x = 4y \\ 2y = 233 \end{cases} $$

$$ \begin{cases} x = 466 \\ y = 116.5 \end{cases} $$

Ответ: в первой цистерне было 466 литров молока, а во второй - 116.5 литров.Ответь+подробно.++Срочно+даю+80баллов+++В+первой+цистерне+было+4+раза+больше+молока,чем+во+второй.Когда+из+первой+цистерны+отлили+137+л+молока+,а+во+вторую+налили+48+л,то+воды+в+первой+цистерне+молока+стало+в+два+раза+меньше,чем+во+второй.Сколько+литров+молока+было+в+каждой+цестерне+первоначально?+

Answer 3

Problem Analysis

We are given information about two tanks, where the first tank initially contains four times more milk than the second tank. After pouring 137 liters of milk from the first tank into the second tank and pouring 48 liters of water into the first tank, the amount of milk in the first tank becomes half of the amount of milk in the second tank. We need to determine the initial amount of milk in each tank.

Solution

Let's assume the initial amount of milk in the second tank is x liters. According to the given information, the first tank initially contains four times more milk than the second tank, so the initial amount of milk in the first tank is 4x liters.

After pouring 137 liters of milk from the first tank into the second tank, the amount of milk in the first tank becomes 4x - 137 liters, and the amount of milk in the second tank becomes x + 137 liters.

After pouring 48 liters of water into the first tank, the amount of milk in the first tank becomes half of the amount of milk in the second tank. Mathematically, we can represent this as:

(4x - 137) = (x + 137) / 2

To solve this equation, we can simplify it as follows:

8x - 274 = x + 137

Simplifying further:

7x = 411

Dividing both sides by 7:

x = 411 / 7

Evaluating the expression:

x ≈ 58.71

Therefore, the initial amount of milk in the second tank is approximately 58.71 liters. Since the first tank initially contains four times more milk than the second tank, the initial amount of milk in the first tank is approximately 4 * 58.71 = 234.84 liters.

So, initially, there were approximately 234.84 liters of milk in the first tank and approximately 58.71 liters of milk in the second tank.

Please note that the given problem does not provide any specific units for the measurements, so we have assumed liters for consistency.

Let me know if you need any further assistance!