
2. Розв'яжи задачу. За 5 год учень столяра виготовив стільки деталей, скільки майс тер — за 3
год. Скільки деталей зробив учень, якщо разом за одну годину вони виготовляють 32 деталей Даю 15 балов

Ответы на вопрос

Ответ:
Пошаговое объяснение:
Пусть ученик изготовил Х деталей
Мастер Y
X + Y = 32 детали/ час
Ученик за 5 часов изготовил 5 Х деталей
Мастер за 3 часа изготовил 3 Y деталей
5 Х = 3 Y
X = 32-Y
5 Х = 3 Y
5 ( 32- Y) = 3 Y
160 -5Y = 3Y
160 = 8 Y,
Y = 160/8
Y = 20 деталей - мастер
X = 32-Y = 32-20 = 12 деталей - ученик.
Проверяем за 3 часа мастер сделает 60 деталей, учение за 5 часов также 60 деталей.



Task Solution
To solve this problem, we can use the concept of proportionality. Let's denote the number of details made by the apprentice in 5 hours as A, and the number of details made by the master in 3 hours as B. We are given that together they make 32 details in 1 hour.
Using the concept of proportionality, we can set up the following equation:
Apprentice's rate: A details / 5 hours = A/5 details per hour Master's rate: B details / 3 hours = B/3 details per hour
Given that together they make 32 details in 1 hour, we can express their combined rate as:
A/5 + B/3 = 32 details per hour
Now, we can solve for A and B to find the number of details made by the apprentice and the master.
Calculation
To solve for A and B, we can use the equation A/5 + B/3 = 32 and solve for A.
Multiplying the equation by 15 (the least common multiple of 5 and 3) to clear the denominators, we get:
3A + 5B = 480
Now, we need another equation to solve for A and B. We know that the apprentice made A details in 5 hours and the master made B details in 3 hours. Since they make the same number of details in 1 hour, we can express this as:
A/5 = B/3
Cross-multiplying, we get:
3A = 5B
Now, we have a system of equations: 3A + 5B = 480 3A = 5B
Solving this system of equations will give us the values of A and B, which represent the number of details made by the apprentice and the master, respectively.
Solution
Solving the system of equations, we find: A = 200 B = 120
So, the apprentice made 200 details, and the master made 120 details.
Therefore, the apprentice made 200 details in 5 hours.


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