Question

В сиропе было 20% сахара, часть воды испорилась, сахара стало 40%. Сколько грамм воды испорилась, если изначально масса раствора весила 1 кг?

Answer 1

Ответ:

500 г

Пошаговое объяснение:

изначально сахара было 0,2×1=0,2(кг)=200 г, воды - 1-0,2=0,8(кг)=800 г

40%-го раствора стало 200:0,4=500(г), воды в нем стало 500-200=300(г)

воды испарилось 800-300=500(г)

Answer 2

Calculating the Amount of Spoiled Water in the Syrup

To calculate the amount of water spoiled in the syrup, we can use the following steps:

1. Determine the Initial Amount of Sugar and Water in the Syrup: - The syrup initially contained 20% sugar, which means the remaining 80% was water. - Given that the initial mass of the solution was 1 kg, the initial amount of sugar can be calculated as 20% of 1 kg, which is 0.2 kg.

2. Calculate the Final Amount of Sugar and Water in the Syrup: - After the water spoiled, the syrup contained 40% sugar, which means the remaining 60% was water.

3. Calculate the Final Amount of Sugar: - The final amount of sugar can be calculated as 40% of the total mass of the solution, which is 0.4 kg.

4. Calculate the Final Amount of Water: - The final amount of water can be calculated as the difference between the total mass of the solution and the final amount of sugar.

Let's calculate the final amount of water in the syrup based on these steps.