Question

Решите задачу срочно... Из группы спортсменов по гребле в которую входят четыре человека - Андреев, Гришин, Степанов, Николаев тренер выделяет двоих для участия в соревнованиях пар. Сколько существует вариантов выбора пары.​

Answer 1

Ответ:

6 пар

Пошаговое объяснение:

1. Андреев и Гришин

2. Андреев и Степанов

3. Андреев и Николаев

4. Гришин и Степанов

5. Гришин и Николаев

6. Степанов и Николаев

Answer 2

Ответ:

6 пар

Пошаговое объяснение:

Answer 3

Problem Analysis

We are given a group of four athletes: Andreev, Grishin, Stepanov, and Nikolaev. The coach wants to select two athletes from this group to form a pair for a competition. We need to determine the number of possible pair combinations.

Solution

To find the number of possible pair combinations, we can use the combination formula. The formula for finding the number of combinations of selecting r items from a set of n items is given by:

C(n, r) = n! / (r! * (n-r)!)

In this case, we need to select 2 athletes from a group of 4. Therefore, the formula becomes:

C(4, 2) = 4! / (2! * (4-2)!)

Simplifying the expression:

C(4, 2) = 4! / (2! * 2!) = (4 * 3 * 2 * 1) / ((2 * 1) * (2 * 1)) = 6

Therefore, there are 6 possible pair combinations that can be formed from the group of four athletes.

Answer

There are 6 possible pair combinations that can be formed from the group of four athletes: Andreev, Grishin, Stepanov, and Nikolaev.