Question

42:z-1=6, 79+44:z=83, 40*z-130=70

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Ответ:

1)42:z-1=6

z=6

2)79+44:z=83

z=11

3)40*z-130=70

z=5

Пошаговое объяснение:

1)42:z-1=6

42:z=6+1

42:z=7

z=42:7

z=6

2)79+44:z=83

44:z=83-79

44:z=4

z=44:4

z=11

3)40*z-130=70

40*z=70+130

40*z=200

z=200:40

z=5

Answer 3

Let's solve the equations one by one:

1. 42:z-1=6

To solve this equation, we'll isolate the variable "z" by performing the necessary operations:

42/z - 1 = 6

42/z = 6 + 1

42/z = 7

To eliminate the fraction, we can cross-multiply:

42 = 7z

Divide both sides of the equation by 7:

42/7 = z

z = 6

Therefore, the solution to the equation is z = 6.

2. 79+44:z=83

Again, we'll isolate the variable "z" by performing the necessary operations:

44/z = 83 - 79

44/z = 4

To eliminate the fraction, we can cross-multiply:

44 = 4z

Divide both sides of the equation by 4:

44/4 = z

z = 11

Therefore, the solution to the equation is z = 11.

3. 40*z-130=70

To solve this equation, we'll isolate the variable "z" by performing the necessary operations:

40z - 130 = 70

Add 130 to both sides of the equation:

40z = 70 + 130

40z = 200

Divide both sides of the equation by 40:

z = 200/40

z = 5

Therefore, the solution to the equation is z = 5.

To summarize, the solutions to the given equations are:

1. z = 6
2. z = 11
3. z = 5