
2) ||x|-7|=5. 3) ||x|-10|=2


Ответы на вопрос

Ответ:
Пошаговое объяснение:
2) |x|-7=5; |x|=12; x1=12 x2=-12
|x|-7=-5; |x|=2; x3=2 x4=-2
3) |x|-10=2; |x|=12; x1=12 x2=-12
|x|-10=-2; |x|=8; x3=8 x4=-8



To solve these absolute value equations, we'll consider the two possible cases for each equation.
Case 1: (x - 7) is positive: In this case, we have: |x| - 7 = 5
Adding 7 to both sides: |x| = 12
Since (x - 7) is positive, x must be greater than 7. Thus, the equation simplifies to: x = 12
Case 2: (x - 7) is negative: In this case, we have: -(x - 7) = 5
Expanding the equation: -x + 7 = 5
Subtracting 7 from both sides: -x = -2
Multiplying both sides by -1 (to get x by itself): x = 2
Therefore, the solutions for the equation ||x| - 7| = 5 are x = 2 and x = 12.
Now let's solve the second equation:
Case 1: (x - 10) is positive: In this case, we have: |x| - 10 = 2
Adding 10 to both sides: |x| = 12
Since (x - 10) is positive, x must be greater than 10. Thus, the equation simplifies to: x = 12
Case 2: (x - 10) is negative: In this case, we have: -(x - 10) = 2
Expanding the equation: -x + 10 = 2
Subtracting 10 from both sides: -x = -8
Multiplying both sides by -1 (to get x by itself): x = 8
Therefore, the solutions for the equation ||x| - 10| = 2 are x = 8 and x = 12.


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