Question

- If (s-3)2=0, what is the value of (s+3)(s+5)? (A) 48 (B) 24 (C) 15 (D) 0 C 13

Answer 1

Ответ:

B) 24

Пошаговое объяснение:

1) (s - 3) × 2 = 0

s - 3 = 0 2 ≠ 0

s = 0 + 3 = 3

2) (3 + 3)(3 + 5) = 6 × 8 = 24

Answer 2

To find the value of (s+3)(s+5), we can start by expanding the expression (s-3)² = 0:

(s-3)² = 0 s² - 6s + 9 = 0

Now, let's expand (s+3)(s+5):

(s+3)(s+5) = s² + 3s + 5s + 15 = s² + 8s + 15

Since we know that (s-3)² = 0, we can substitute s² - 6s + 9 = 0 into the expanded expression:

(s+3)(s+5) = (s² + 8s + 15) = (s² - 6s + 9) + 8s + 15 = s² + 2s + 24

So, the value of (s+3)(s+5) is 24.

Therefore, the correct answer is (B) 24.