Question

№455 (3b-1)²(5z+2)²(4x-5y)²№457(4-b)²+8b-b²№459(x-1)²-x²=11​

Answer 1

Ответ:

455

9b²-6b+1

25z²+20z+4

16x²-40x y+25y²

457

16

459

x= -5

Пошаговое объяснение:

да вот так

Answer 2

Let's solve the equation step by step:

№455: (3b-1)²(5z+2)²(4x-5y)² Expanding this expression, we have:

(9b² - 6b + 1)(25z² + 20z + 4)(16x² - 40xy + 25y²)

№457: (4-b)² + 8b - b² Expanding this expression, we have:

(16 - 8b + b²) + 8b - b² Simplifying, we get:

16 + 8b - 8b + b² - b² The middle terms cancel out, and we are left with:

16

№459: (x-1)² - x² = 11 Expanding the left side, we have:

(x² - 2x + 1) - x² = 11 Simplifying, we get:

-x² + 2x + 1 - x² = 11 Combining like terms, we have:

-2x² + 2x + 1 = 11 Rearranging the equation, we get:

-2x² + 2x + 1 - 11 = 0 -2x² + 2x - 10 = 0

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = -2, b = 2, and c = -10. Plugging these values into the formula, we have:

x = (-2 ± √(2² - 4(-2)(-10))) / (2(-2)) x = (-2 ± √(4 - 80)) / (-4) x = (-2 ± √(-76)) / (-4)

Since we have a negative value inside the square root, the equation has no real solutions.