Question

Sin(3пи/2 + альфа)= cos(3пи/2 + альфа)=

Answer 1

Sin(3пи/2 + альфа)=-cos(альфа)
cos(3пи/2 + альфа)=sin(альфа)

Answer 2

sin(3пи/2 + альфа)= -cosальфа
cos(3пи/2 + альфа)= sinальфа

Answer 3

In general, the sine and cosine functions have specific values for certain angles. Let's evaluate the expressions you provided:

sin(3π/2 + α) = cos(π/2 - α) = -cos(α)

cos(3π/2 + α) = -sin(α)

By using the periodicity and symmetry properties of sine and cosine functions, we can simplify the expressions as shown above.