Question

(12:а+b):1 1/2-c при a=3 3/5, b=2/3,c=1 1/3

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To evaluate the expression (12:(a+b)):(1 1/2-c) with the given values a = 3 3/5, b = 2/3, and c = 1 1/3, we need to substitute these values into the expression and simplify the calculation step by step.

First, let's convert the mixed numbers into improper fractions:

a = 3 3/5 = (53 + 3)/5 = 18/5 c = 1 1/3 = (31 + 1)/3 = 4/3

Now, we can substitute the values into the expression:

(12:(a+b)):(1 1/2-c) = (12:(18/5 + 2/3)):(1 1/2 - 4/3)

Next, let's simplify the expression inside the parentheses:

a+b = 18/5 + 2/3 = (183 + 52)/(5*3) = (54 + 10)/15 = 64/15

Substituting this back into the original expression:

(12:(a+b)):(1 1/2-c) = (12:(64/15)):(1 1/2 - 4/3)

Now, let's simplify the expression inside the first set of parentheses:

12:(64/15) = 12 * (15/64) = (12*15)/64 = 180/64 = 45/16

Substituting this back into the original expression:

(45/16):(1 1/2-c) = 45/16:(1 1/2 - 4/3)

Now, let's simplify the expression inside the second set of parentheses:

1 1/2 - 4/3 = (31 + 2)/2 - (34 + 1)/3 = (5/2) - (13/3)

To subtract fractions with different denominators, we need to find a common denominator. In this case, the least common multiple of 2 and 3 is 6.

(5/2) - (13/3) = (5/2)(3/3) - (13/3)(2/2) = 15/6 - 26/6 = (15 - 26)/6 = -11/6

Substituting this back into the original expression:

45/16:(-11/6) = 45/16 * (-6/11) = (45*(-6))/(16*11) = -270/176 = -135/88

Therefore, the value of the expression (12:(a+b)):(1 1/2-c) with a = 3 3/5, b = 2/3, and c = 1 1/3 is -135/88.