Question

2)(X)-1,3=1,2 3)(X)-0,8=-0,1 4)(X)+2,1=1 5)13-(X)=6 6)(X+2,1)=3 ПЕРВОЕ СДЕЛАЛИ СДЕЛАЕТЕ ОСТАЛЬНЫЕ ПЖ

Answer 1

2)х-1,3=1,2 3)х-0,8=-0,1 6)(х+2,1)=3
х=1,2+1,3 х=-0,1+0,8 х=3-2,1
х=2,5 х=0,7 х=0,7
4)х+2,1=1 5)13-х=6
х=1-2,1 -х=6-13
х=-1,1 -х=-7
х=7

Answer 2

2. To solve for X in (X)-1,3=1,2, you can add 1,3 to both sides of the equation to isolate X:

(X) - 1,3 + 1,3 = 1,2 + 1,3

(X) = 2,5

Therefore, X = 2,5.

3. To solve for X in (X)-0,8=-0,1, you can add 0,8 to both sides of the equation to isolate X:

(X) - 0,8 + 0,8 = -0,1 + 0,8

(X) = 0,7

Therefore, X = 0,7.

4. To solve for X in (X)+2,1=1, you can subtract 2,1 from both sides of the equation to isolate X:

(X) + 2,1 - 2,1 = 1 - 2,1

(X) = -1,1

Therefore, X = -1,1.

5. To solve for X in 13-(X)=6, you can subtract 6 from both sides of the equation to isolate X:

13 - (X) - 6 = 6 - 6

7 - (X) = 0

Next, you can add X to both sides of the equation:

7 - (X) + (X) = 0 + (X)

7 = X

Therefore, X = 7.

6. To solve for X in (X+2,1)=3, you can subtract 2,1 from both sides of the equation to isolate X:

(X+2,1) - 2,1 = 3 - 2,1

(X) = 0,9

Therefore, X = 0,9.