Question

-2|х+1|+4/31=-1/32 пж​

Answer 1

Ответ:

-2|x+1|= -1/32-4/31

-2|x+1|=-159/992

|x+1|=159/1984

x+1=159/1984

x+1= -159/1984

x= - 1825/1984

x= -2143/1984

x1= -1825/1984; x2= -2143/1984

Answer 2

To solve this equation, we need to isolate the absolute value term, which is -2|х+1|.

First, we can start by subtracting 4/31 from both sides of the equation:

-2|х+1| = -1/32 - 4/31

Next, we can simplify the right-hand side by finding a common denominator:

-2|х+1| = (-31 - 128)/31*32

-2|х+1| = -159/992

Then, we can divide both sides by -2, which will cause the absolute value to disappear:

|х+1| = (-159/992)/(-2)

|х+1| = 159/1984

At this point, we have two cases to consider, depending on whether х+1 is positive or negative:

Case 1: х+1 is positive

If х+1 is positive, then |х+1| = х+1, so we have:

х+1 = 159/1984

Solving for х, we get:

х = 159/1984 - 1

х = -825/992

Case 2: х+1 is negative

If х+1 is negative, then |х+1| = -(х+1), so we have:

-(х+1) = 159/1984

Solving for х, we get:

х = -(159/1984 + 1)

х = -3143/1984

Therefore, the two solutions to the equation are:

х = -825/992 or х = -3143/1984.