Question

{ 6 ( x − 2 ) − 4 ≥ − 2 ( 3 + x ) + 2 − 4 ( x + 1 ) + 5 < 2 ( 5 − x ) − 1

Answer 1

6(х-2)->=-2(3+х)+2-4(х+1)+5<2(5-х)-1
6х-12>=-6-2х+2-4х-4+5<10-2х-1
6х-12>=-3-6х<9-2х
дальше я незнаю

Answer 2

Let's solve the inequalities step by step:

6(x-2)-4 ≥ -2(3+x)+2-4(x+1)+5

Simplifying the left side:

6x - 12 - 4 ≥ -6 - 2x + 2 - 4x - 4 + 5

6x - 16 ≥ -6 - 6x

Adding 6x to both sides:

12x - 16 ≥ -6

Adding 16 to both sides:

12x ≥ 10

Dividing by 12:

x ≥ 5/6

So the solution to the first inequality is x ≥ 5/6.

Now let's move to the second inequality:

2(5-x)-1 < 2

Simplifying the left side:

10 - 2x - 1 < 2

9 - 2x < 2

Subtracting 9 from both sides:

-2x < -7

Dividing by -2 (and reversing the inequality):

x > 7/2

So the solution to the second inequality is x > 7/2.

Putting it all together, we have:

x ≥ 5/6 AND x > 7/2

The only numbers that satisfy both of these conditions are values of x greater than 7/2, so the solution is:

x > 7/2