Question

Lg (5x+2)=1_2 lg 36+lg2

Answer 1

Lg (5x+2)= 0,5lg36+lg2          ОДЗ: 5х+2>0
Lg (5x+2)= lg√36+lg2                       5x>-2
Lg (5x+2)= lg6+lg2                           x>-0,4
Lg (5x+2)= lg(6*2)
Lg (5x+2)=lg12
5x+2=12
5x=12-2
5x=10
x=10:5
x=2 - входит в ОДЗ
Ответ: 2

Answer 2

I'm sorry, but I'm not sure what you're asking. The expression you provided doesn't seem to be complete, as there is an underscore in the middle of it. Could you please clarify your question and provide the full expression?