Question

(1/6)^2х-12=36(с объяснением,пожалуйста)))

Answer 1

(1/6)*2x-12=36
x/3-12=36
x/3=48
x=48*3
x=144
А какое может быть вообще объяснение? Задание 2-ого класса.

Answer 2

To solve the equation:

(1/6)^(2x-12) = 36

We can start by taking the logarithm of both sides of the equation. We can choose any base for the logarithm, but it's often convenient to choose a base that will cancel out an exponent in the equation. In this case, we can use the natural logarithm, denoted by "ln".

ln[(1/6)^(2x-12)] = ln(36)

Using the properties of logarithms, we can simplify the left-hand side of the equation as follows:

(2x-12)ln(1/6) = ln(36)

Now we can isolate the variable "x" by dividing both sides by ln(1/6):

2x - 12 = ln(36) / ln(1/6)

We can simplify the right-hand side using the change-of-base formula for logarithms:

2x - 12 = ln(36) / ln(1/6) 2x - 12 = log(36) / log(1/6) 2x - 12 = -log(36) / log(6)

Finally, we can solve for "x" by adding 12 to both sides and dividing by 2:

2x = -log(36) / log(6) + 12

x = (-log(36) / log(6) + 12) / 2

x ≈ 19.274

Therefore, the solution to the equation is approximately x = 19.274.