Question

2^3x-26 =(1/16)^2x+1

Answer 1

${2}^{3x - 26} = {2}^{ - 4 \times (2x + 1)}$
${2}^{3x - 26} = {2}^{ - 8x - 4}$
$3x - 26 = - 8x - 4$
$3x + 8x = - 4 + 26$
$11x = 22$
$x = 2$

Таким образом, x равен 2

Ответ: 2

Answer 2

To solve the equation 2^(3x-26) = (1/16)^(2x+1), we can start by expressing both sides with a common base. We know that 2 is the reciprocal of (1/2), so we can rewrite (1/16) as 2^(-4):

2^(3x-26) = (1/16)^(2x+1)

2^(3x-26) = 2^(-4(2x+1))

Now that both sides have a common base of 2, we can equate the exponents:

3x-26 = -8x-4

Solving for x, we get:

3x + 8x = 26 - 4

11x = 22

x = 2

Therefore, the solution to the equation 2^(3x-26) = (1/16)^(2x+1) is x=2.