Question

1) 5 ( 27a + 3 ) + 7 (11a-21)= 2) 23 (4b + 7 ) + 9 (32b - 7 ) cрочно заранее спасибо

Answer 1

Ответ:

1)5(27a+3)+7(11a-21)=27а+15+11а-147=(27а+11а)+(15-147)=38а-132

2)23(4b+7)+9(32b-7)=4b+161+32b-63=(4b+32b)+(161-63)=36b+98

Пошаговое объяснение:

Answer 2

1. Let's simplify the left side of the equation by distributing the terms:

5(27a+3) + 7(11a-21) = 135a + 15 + 77a - 147

Combining like terms, we get:

212a - 132 = 0

Adding 132 to both sides, we get:

212a = 132

Dividing both sides by 212, we get:

a = 0.6226 (rounded to four decimal places)

Therefore, the solution to the equation is a = 0.6226.

2. Following the same process, we distribute the terms on the left side of the equation:

23(4b+7) + 9(32b-7) = 92b + 161 + 288b - 63

Combining like terms, we get:

380b + 98 = 0

Subtracting 98 from both sides, we get:

380b = -98

Dividing both sides by 380, we get:

b = -0.2579 (rounded to four decimal places)

Therefore, the solution to the equation is b = -0.2579.