Question

Решите (3x+2)/(x-1)=(7(x+3)-2(2x+5)-9)/(x-1)​

Answer 1

Ответ:

х- любое число кроме 1

Пошаговое объяснение:

$\frac{(3x+2)}{(x-1)} =\frac{7(x+3)-2(2x+5)-9}{x-1} \\ \\ \frac{3x+2}{x-1} =\frac{7x+21-4x-10-9}{x-1} \\ \\ \frac{3x+2}{x-1} =\frac{3x+2}{x-1} \\ \\ x-1\neq 0\\ x\neq 1$

Answer 2

To solve the equation (3x+2)/(x-1)=(7(x+3)-2(2x+5)-9)/(x-1), we can start by simplifying the expression on the right side of the equation:

7(x+3)-2(2x+5)-9 = 7x + 21 - 4x - 10 - 9 = 3x + 2

So now we have:

(3x+2)/(x-1) = (3x+2)/(x-1)

Since both sides of the equation are equal, the equation holds true for all values of x, except for x = 1, where the denominator becomes zero and the expression is undefined. Therefore, the solution to the equation is all real numbers except x = 1. We can write this solution as:

x ≠ 1