Question

Найдите разность 1/3-1/5 3/5-1/7 1/3-1/6 9/14-2/7 5/6-3/8 9/14-9/21

Answer 1

◕‿◕◕‿◕** Решение во вложении **.◕‿◕◕‿◕

Answer 2

$\frac{1}{3}- \frac{1}{5}= \frac{5-3}{15}= \frac{2}{15} \\ \\ \frac{3}{5}- \frac{1}{7}= \frac{21-5}{35}= \frac{16}{35} \\ \\ \frac{1}{3}- \frac{1}{6}= \frac{2-1}{6}=\frac{1}{6}\\ \\ \frac{9}{14}- \frac{2}{7}= \frac{9-4}{14}= \frac{5}{14} \\ \\ \frac{5}{6}- \frac{3}{8}= \frac{20-9}{24}= \frac{11}{24} \\ \\ \frac{9}{14}- \frac{9}{21}= \frac{27-18}{42}= \frac{9}{42}= \frac{3}{14}$

Answer 3

Для вычисления разности дробей нужно сначала привести их к общему знаменателю и вычислить числитель разности.

1/3 - 1/5 = (5/15) - (3/15) = 2/15 3/5 - 1/7 = (21/35) - (5/35) = 16/35 1/3 - 1/6 = (2/6) - (1/6) = 1/6 9/14 - 2/7 = (9/14) - (4/14) = 5/14 5/6 - 3/8 = (20/24) - (9/24) = 11/24 9/14 - 9/21 = (27/42) - (18/42) = 9/42 = 3/14

Итак, разность заданных дробей равна: 2/15 - 16/35 + 1/6 - 5/14 + 11/24 - 3/14 = = (168)/(158) - (1214)/(3512) + (74)/(64) - (103)/(143) + (117)/(247) - (62)/(142) = = 128/120 - 168/420 + 28/24 - 30/42 + 77/168 - 12/28 = = 32/30 - 4/5 + 7/6 - 5/7 + 11/24 - 3/7 = = (162)/(152) - 4/5 + (357)/(356) - (305)/(307) + 11/24 - (83)/(78) = = 32/30 - 4/5 + 35/42 - 150/210 + 11/24 - 24/56 = = 16/15 - 4/5 + 5/6 - 5/3 + 11/24 - 6/14 = = 32/30 - 24/30 + 25/30 - 50/30 + 55/120 - 30/70 = = (32 - 24 + 25 - 50)2/60 + (55 - 30)7/840 = = 2/15 + 7/120 = = (162)/(152) + (157)/(12015) = = 32/30 + 7/120 = = 16/15 + 7/60 = = (164)/(154) + (157)/(6015) = = 64/60 + 7/60 = = 71/60.

Ответ: 71/60.