Question

1.Корень 10+3x=x+4 2.Корень 11+5х=х+3 3. Корень 2х-5=4-х 4. Корень 5-2х= х-1

Answer 1

1)3х-х=4-10
2х=-6
х=-3

2)5х-х=3-11
4х=-8
х=-2

3)2х+х=4+5
3х=9
х=3

4)-2х-х=-1-5
-3х=-6
х=2

Answer 2

1. Корень 10 + 3x = x + 4: First, let's isolate the square root by subtracting x from both sides:

√(10 + 3x - x) = √(10 + 2x) = √(x + 4)

Now, let's square both sides to eliminate the square root:

10 + 2x = x + 4

Simplifying:

x = -2

Therefore, the solution is x = -2.

2. Корень 11 + 5x = x + 3: Again, let's isolate the square root by subtracting x from both sides:

√(11 + 5x - x) = √(11 + 4x) = √(3)

Squaring both sides:

11 + 4x = 3

Simplifying:

x = -2

Therefore, the solution is x = -2.

3. Корень 2x - 5 = 4 - x: Isolating the square root:

√(2x - 5) = 4 - x

Squaring both sides:

2x - 5 = 16 - 8x + x^2

Rearranging:

x^2 - 10x + 21 = 0

Factoring:

(x - 7)(x - 3) = 0

Therefore, the solutions are x = 7 and x = 3.

4. Корень 5 - 2x = x - 1: Isolating the square root:

√(5 - 2x) = x - 1

Squaring both sides:

5 - 2x = x^2 - 2x + 1

Rearranging:

x^2 = 6

Taking the square root:

x = ±√6

Therefore, the solutions are x = √6 -or- x = -√6.