Question

Решите1)2x+10=202)4x-40=603)2/5x+1/5=4/54)2x+5y=40

Answer 1

1) x = (20 - 10) : 2 = 5

2) x = (60 - 40) : 4 = 5

3) x = (4/5 - 1/5) : 2/5 = 0.3 = 3/10

4) x = 5, y = 6; или x = 10, y = 4; или x = 15, y = 2

Answer 2

We can start by isolating x on one side of the equation.

2x + 10 = 20

Subtracting 10 from both sides:

2x = 10

Dividing both sides by 2:

x = 5

Therefore, the solution is x = 5.

Similar to the previous problem, we can isolate x by moving the constant term to the other side of the equation.

4x - 40 = 60

Adding 40 to both sides:

4x = 100

Dividing both sides by 4:

x = 25

Therefore, the solution is x = 25.

We can start by isolating x on one side of the equation.

2/5x + 1/5 = 4/5

Subtracting 1/5 from both sides:

2/5x = 3/5

Multiplying both sides by 5/2:

x = (3/5) * (5/2)

x = 3/2

Therefore, the solution is x = 3/2.

This is a system of two equations in two variables. We can use substitution or elimination to solve for x and y.

Let's use substitution.

From the first equation, we can solve for y:

y = (40 - 2x)/5

Substituting this expression for y into the second equation:

2x + 5((40-2x)/5) = 40

Simplifying:

2x + 40 - 10x = 40

-8x = 0

x = 0

Substituting x = 0 into the expression we found for y:

y = (40 - 2(0))/5 = 8

Therefore, the solution is x = 0, y = 8.