Question

38x(2)-(13x(2)+121) при x = 5. если x = 5 то 38 x(2)-(13 x(2) + 121=

Answer 1

Как я понимаю (2) - это квадрат. Если так, то вот:
38х2-(13х2+121)=38*5(2)-(13*5(2)+121)=38*25-(13*25+121)=950-446=504.

Answer 2

To evaluate the expression 38x^2 - (13x^2 + 121) for x = 5, we substitute the value of x into the expression:

38(5^2) - (13(5^2) + 121)

First, we calculate the values within parentheses:

38(25) - (13(25) + 121)

Next, we perform the multiplications:

950 - (325 + 121)

Inside the parentheses, we simplify the addition:

950 - (446)

Finally, we perform the subtraction:

504

Therefore, when x = 5, the value of the expression 38x^2 - (13x^2 + 121) is 504.