Question

SinA=1/2, sinB =1/3, b=6. найдите a

Answer 1

По теореме синусов a/sin A=b/sin B.    a=b*sin A/sin B=6*1/2:1/3=9

Answer 2

A/sina=b/sinb
a=(sina ×b) / sin b
a= (1/2 × 6) / 1/3
a=9

Answer 3

To find the value of 'a' given that sin(A) = 1/2, sin(B) = 1/3, and b = 6, we can use the sine rule for triangles.

The sine rule states that in a triangle, the ratio of the length of a side to the sine of its opposite angle is constant. This can be written as:

a/sin(A) = b/sin(B)

Substituting the given values, we have:

a/(1/2) = 6/(1/3)

To simplify, we can multiply both sides of the equation by 2 and 3:

2a = 6 * 2/1 2a = 12

Dividing both sides by 2:

a = 12/2 a = 6

Therefore, the value of 'a' is 6.