Question

2a+b/a(в квадрате)-b(в квадрате)+1/a+b

Answer 1

$\frac{2a+b}{a^2-b^2}+ \frac{1}{a+b} = \frac{2a+b}{a^2-b^2}+ \frac{a-b}{a^2-b^2} = \frac{2a+b+a-b}{a^2-b^2} = \frac{3a}{a^2-b^2}$

Answer 2

The expression you provided is:

2a + b / a^2 - b^2 + 1 / (a + b)

To simplify this expression, let's break it down into separate terms and simplify each one individually.

Term 1: 2a This term is already in its simplest form and cannot be further simplified.

Term 2: b / (a^2 - b^2) The denominator can be factored as a difference of squares: (a + b)(a - b). Therefore, the expression can be rewritten as:

b / ((a + b)(a - b))

Term 3: 1 / (a + b) This term is already in its simplest form and cannot be further simplified.

Now let's combine the simplified terms:

2a + b / ((a + b)(a - b)) + 1 / (a + b)

Since the denominator of the second term and the denominator of the third term share the factor (a + b), we can combine them into a single fraction:

2a + (b + 1) / ((a + b)(a - b))

This is the simplified form of the expression.