Question

А)22°15′ + 4°30′ Б)4°16′36″ + 34°43′26″ В)45°50′ - 34°17′ Г)5°13′45″ - 3°20′33″

Answer 1

1)22°15´+4°30´= 26°45´
2)4°16´36´´+34°43´26´´=39°0´2´´(36´´+26´´=1´2´´,16´+43´+1´=60´=1°)
3)45°50´-34°17´=11°33´
4)5°13´45´´-3°20´33´´=4°73´45´´-3°20´33´´=1°53´12´´

Answer 2

A) To add 22°15′ and 4°30′, we add the degrees and the minutes separately:

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Degrees: 22 + 4 = 26

Minutes: 15 + 30 = 45

Therefore, the sum is 26°45′.

B) To add 4°16′36″ and 34°43′26″, we add the degrees, minutes, and seconds separately:

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Degrees: 4 + 34 = 38

Minutes: 16 + 43 = 59

Seconds: 36 + 26 = 62 (Note that there are 60 seconds in 1 minute, so we carry over 1 minute)

Therefore, the sum is 38°59′62″, but we need to simplify this to the correct format:

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Minutes: 59 + 1 (the carried over minute) = 60, so we write 0 in the seconds place and carry over 1 minute.

Degrees: 38 + 1 (the carried over minute) = 39

Therefore, the sum is 39°00′00″.

C) To subtract 34°17′ from 45°50′, we subtract the degrees and the minutes separately:

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Degrees: 45 - 34 = 11

Minutes: 50 - 17 = 33

Therefore, the difference is 11°33′.

D) To subtract 3°20′33″ from 5°13′45″, we subtract the degrees, minutes, and seconds separately:

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Degrees: 5 - 3 = 2

Minutes: 13 - 20 = -7 (Note that we need to borrow 1 degree from the degrees place to do this subtraction)

Seconds: 45 - 33 = 12

Therefore, the difference is 2°(60-7)′12″, but we need to simplify this to the correct format:

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Minutes: 60 - 7 = 53

Therefore, the difference is 2°53′12″.