Question

Log0,45 (10x+3) <= log0,45 2x

Answer 1

Ответ:

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Пошаговое объяснение:

Answer 2

To solve the inequality:

log₀.₄₅(10x+3) ≤ log₀.₄₅(2x)

We can use the property of logarithms that states:

logₐ(b) ≤ logₐ(c) if and only if b ≤ c (for a > 1)

In this case, a = ₀.₄₅, and both sides have the same base, so we can drop the logarithm notation and write:

10x + 3 ≤ 2x

Now we can solve this inequality for x:

10x - 2x + 3 ≤ 0

8x + 3 ≤ 0

8x ≤ -3

x ≤ -3/8

Therefore, the solution to the inequality log₀.₄₅(10x+3) ≤ log₀.₄₅(2x) is x ≤ -3/8.