Question

X^2-6x+13 (2b+1)^2-(b+2)^2 Help me please!!!!!!

Answer 1

$(2b+1)^2-(b+2)^2=(2b+1-(b+2))(2b+1+b+2)=$ $(2b+1-b-2)(3b+3)=(b-1)*3(b+1)$

Answer 2

X2-6x+13
По формуле дискрименанта
36-4*1*13=-16ответ уравнение не имеет корней

Answer 3

Let's break down the expressions you provided:

1. X^2 - 6x + 13 This is a quadratic expression in terms of 'x'. To simplify it further, we can check if it can be factored or if it requires using the quadratic formula. However, it seems that you didn't specify any instructions for this expression, so I'll leave it as is for now.

2. (2b + 1)^2 - (b + 2)^2 This expression involves binomial squares. We can simplify it using the difference of squares formula, which states that a^2 - b^2 = (a + b)(a - b). Applying this to the given expression, we have:

(2b + 1)^2 - (b + 2)^2 [(2b + 1) + (b + 2)][(2b + 1) - (b + 2)]

Simplifying further:

(3b + 3)(b - 1) 3(b + 1)(b - 1)

So, the simplified form of the expression (2b + 1)^2 - (b + 2)^2 is 3(b + 1)(b - 1).

If you have any additional questions or if there's anything else I can assist you with, please let me know!