Question

(5x – 2y + 4) = 0,6 (2x + 3) - y - 41 = 0;способом подстановки система​

Answer 1

Так

(5х-2у+4)=0

6(2х+3)-у-41=0

Answer 2

Решение во вложениии

Answer 3

To solve the system of equations using the method of substitution, we'll solve one equation for a variable and substitute it into the other equation.

Let's solve the first equation, 5x - 2y + 4 = 0, for x: 5x - 2y + 4 = 0 5x = 2y - 4 x = (2y - 4)/5

Now substitute this expression for x in the second equation, 0.6(2x + 3) - y - 41 = 0: 0.6(2x + 3) - y - 41 = 0 0.6(2((2y - 4)/5) + 3) - y - 41 = 0

Let's simplify this equation:

0.6(2((2y - 4)/5) + 3) - y - 41 = 0 0.6(2(2y - 4)/5 + 3) - y - 41 = 0 0.6(4y - 8)/5 + 0.6(3) - y - 41 = 0 (2.4y - 4.8)/5 + 1.8 - y - 41 = 0 (2.4y - 4.8)/5 - y - 39.2 = 0

Now we can solve for y:

(2.4y - 4.8)/5 - y - 39.2 = 0 2.4y - 4.8 - 5y - 196 = 0 2.4y - 5y - 200.8 = 0 -2.6y - 200.8 = 0 -2.6y = 200.8 y = 200.8 / -2.6 y ≈ -77.23

Now substitute this value of y back into the first equation to find x:

x = (2y - 4)/5 x = (2(-77.23) - 4)/5 x = (-154.46 - 4)/5 x = -158.46/5 x ≈ -31.69

Therefore, the solution to the system of equations is approximately x ≈ -31.69 and y ≈ -77.23.