Question

-6(3х+1)-(х-8)=15; -3(2х+1)-(х-8)=7; -7(3х+6)-(х-8)=-15; -7(2х+3)-(х-5)=-9

Answer 1

-18х-6-х+8=15
-19х+2=15
-19х=13
х=-1 6/3
-6х-3-х+8=7
-7х+5=7
-7х=2
х= -3 1/2
-21х-42-х+8=-15
-22х-34=-15
-22х=9
х= - 2 4/9
-14х-21-х+5=-9
-15х-16=-9
-15х=7
х= -2 1/7

Answer 2

Let's solve each equation step by step:

1. -6(3x+1)-(x-8) = 15

First, apply the distributive property:

-18x - 6 - x + 8 = 15

Combine like terms:

-19x + 2 = 15

Subtract 2 from both sides:

-19x = 13

Divide by -19:

x = -13/19

2. -3(2x+1)-(x-8) = 7

Again, apply the distributive property:

-6x - 3 - x + 8 = 7

Combine like terms:

-7x + 5 = 7

Subtract 5 from both sides:

-7x = 2

Divide by -7:

x = -2/7

3. -7(3x+6)-(x-8) = -15

Distribute:

-21x - 42 - x + 8 = -15

Combine like terms:

-22x - 34 = -15

Add 34 to both sides:

-22x = 19

Divide by -22:

x = -19/22

4. -7(2x+3)-(x-5) = -9

Apply the distributive property:

-14x - 21 - x + 5 = -9

Combine like terms:

-15x - 16 = -9

Add 16 to both sides:

-15x = 7

Divide by -15:

x = -7/15

Therefore, the solutions to the given equations are:

x = -13/19, -2/7, -19/22, -7/15