Question

₄ √80 : √5= ПЕРВЫЙ ПРИМЕР ВТОРОЙ ПРИМЕР (7+√7):(√7+7)=

Answer 1

Думай тродно чтоли и и

Answer 2

1) √80 : √5=√(80/5)=√(16)=4
2)(7+√7):(√7+7)=1

Answer 3

Let's solve each expression step by step:

First expression:

₄√80 : √5

To simplify this expression, we can write 80 and 5 as their prime factorizations:

80 = 2^4 * 5 5 = 5^1

Now let's simplify the expression:

₄√80 : √5 = ₄√(2^4 * 5) : √5 = ₄√(2^4) * ₄√5 : √5 = 2 * ₄√5 : √5

The square root (√5) in the numerator and denominator cancels out, leaving us with:

2 * ₄√5 : √5 = 2 * ₄√5 / √5 = 2 * ₄√(5/1) = 2 * ₄√5 = 2 * √(√5^4) = 2 * √(5^2) = 2 * 5 = 10

Therefore, ₄√80 : √5 equals 10.

Second expression:

(7 + √7) : (√7 + 7)

To simplify this expression, we'll multiply the numerator and denominator by the conjugate of the denominator, which is (√7 - 7).

(7 + √7) : (√7 + 7) = (7 + √7)(√7 - 7) : (√7 + 7)(√7 - 7)

Using the difference of squares formula, we have:

(7 + √7)(√7 - 7) = (√7)^2 - (7)^2 = 7 - 49 = -42

(√7 + 7)(√7 - 7) = (√7)^2 - (7)^2 = 7 - 49 = -42

Therefore, (7 + √7) : (√7 + 7) equals -42/-42 = 1.

In summary:

₄√80 : √5 = 10

(7 + √7) : (√7 + 7) = 1