Question

2.Найти координаты точек А и В пересечения прямой ,заданной уравнением 2х -3у - 12 =0 , с осями координат УМОЛЯЮ , С РЕШЕНИЕМ!!

Answer 1

Finding the Coordinates of Points A and B

To find the coordinates of points A and B, we need to find the intersection of the line given by the equation 2x - 3y - 12 = 0 with the coordinate axes.

Let's start by finding the x-coordinate of point A, which is the point where the line intersects the x-axis. To find this, we set y = 0 in the equation and solve for x:

2x - 3(0) - 12 = 0

Simplifying the equation, we get:

2x - 12 = 0

Adding 12 to both sides:

2x = 12

Dividing both sides by 2:

x = 6

Therefore, the x-coordinate of point A is 6.

Next, let's find the y-coordinate of point B, which is the point where the line intersects the y-axis. To find this, we set x = 0 in the equation and solve for y:

2(0) - 3y - 12 = 0

Simplifying the equation, we get:

-3y - 12 = 0

Adding 12 to both sides:

-3y = 12

Dividing both sides by -3:

y = -4

Therefore, the y-coordinate of point B is -4.

Hence, the coordinates of point A are (6, 0), and the coordinates of point B are (0, -4).

Note: The above solution is based on the given equation and the assumption that the line intersects both the x-axis and the y-axis. If the line is parallel to one of the axes, it will not intersect that axis, and the corresponding coordinate will be undefined.