Question

В треугольнике АВС АВ>ВС>АС. Найдите угол А, угол В и угол С, если известно, что один из углов треугольника равен 120 градусов, а другой 40 градусов. с рисунком

Answer 1

В прикрепленном файле-напротив большей стороны лежит больший угол и тд

Answer 2

Triangle ABC

In triangle ABC, it is given that AB > BC > AC. We need to find the measures of angles A, B, and C, given that one angle of the triangle is 120 degrees and another angle is 40 degrees.

Solution

Let's denote angle A as ∠A, angle B as ∠B, and angle C as ∠C.

Since AB > BC > AC, we can conclude that angle A is the largest angle, angle B is the second largest angle, and angle C is the smallest angle in the triangle.

Given that one angle is 120 degrees and another angle is 40 degrees, we can determine the measure of the remaining angle using the fact that the sum of the angles in a triangle is always 180 degrees.

To find ∠A, we subtract the sum of the other two angles from 180 degrees: ∠A = 180 - (120 + 40) = 180 - 160 = 20 degrees.

Therefore, angle A measures 20 degrees.

To find ∠B, we subtract the sum of the other two angles from 180 degrees: ∠B = 180 - (120 + 20) = 180 - 140 = 40 degrees.

Therefore, angle B measures 40 degrees.

Finally, to find ∠C, we subtract the sum of the other two angles from 180 degrees: ∠C = 180 - (40 + 20) = 180 - 60 = 120 degrees.

Therefore, angle C measures 120 degrees.

Summary

In triangle ABC, with AB > BC > AC, the measures of the angles are as follows: - Angle A (∠A) measures 20 degrees. - Angle B (∠B) measures 40 degrees. - Angle C (∠C) measures 120 degrees.

Please note that the diagram you mentioned was not provided, but the solution above should give you the correct measures of the angles in the given triangle.