Question

Прямые AC и CD пересечены секущей EO в точках K и M соответственно.Угол AKO=120 градусов , Угол EMC в меньше угла AKO Доказать- что AB параллельно CD

Answer 1

Дано АВ и СД-прямые ЕО- СЕКУЩАЯ УГОЛ АКО = 120градусам Угол ЕМС = 60 градусам, значит АКО:ЕМС = 120:60= 2. Вот и все

Answer 2

Given Information

We are given that the lines AC and CD intersect with the secant EO at points K and M respectively. We are also given that angle AKO is 120 degrees and angle EMC is smaller than angle AKO. We need to prove that line AB is parallel to line CD.

Proof

To prove that line AB is parallel to line CD, we need to show that the corresponding angles are equal. Let's consider the angles formed by the lines AC and CD with the secant EO.

1. Angle AKO: We are given that angle AKO is 120 degrees. 2. Angle EMC: We are given that angle EMC is smaller than angle AKO.

Now, let's consider the angles formed by the lines AB and CD with the secant EO.

3. Angle BKO: Since line AB is parallel to line CD, angle BKO is equal to angle AKO. This is because corresponding angles formed by a transversal intersecting parallel lines are equal.

Since angle BKO is equal to angle AKO, and angle EMC is smaller than angle AKO, we can conclude that angle BKO is also smaller than angle EMC.

Therefore, we have shown that angle BKO is smaller than angle EMC. This implies that line AB is parallel to line CD.

Hence, we have proved that AB is parallel to CD.

Note: The given information and proof are based on the available search result snippet.