Question

Дано: ΔABC,BC=CA. Основание треугольника на 7 м больше боковой стороны. Периметр треугольника ABC равен 91 м. Вычисли стороны треугольника. Заранее спасибо

Answer 1

BC=CA=x
AB=X+7
P=AB+BC+AC
x+x+(x+7)=91
3x+7=91
3x=91-7
3x=84
x=84/3=28
AB=28+7=35
BC=CA=28

Answer 2

(91-7):3=28м - стороны ВС и СА
28+7=35м - АВ
Ответ 35м, 28м, 28м

Answer 3

Problem Analysis

We are given a triangle ABC, where BC = CA. The base of the triangle is 7 meters longer than the side. The perimeter of the triangle ABC is 91 meters. We need to calculate the lengths of the sides of the triangle.

Solution

Let's assume that the length of the side BC is x meters. Since BC = CA, the length of side CA is also x meters.

According to the given information, the base of the triangle is 7 meters longer than the side. Therefore, the length of the base AB is (x + 7) meters.

The perimeter of the triangle ABC is the sum of the lengths of all three sides. We can write this as an equation:

Perimeter = BC + CA + AB

Substituting the given values, we have:

91 = x + x + (x + 7)

Simplifying the equation, we get:

91 = 3x + 7

Subtracting 7 from both sides, we have:

84 = 3x

Dividing both sides by 3, we get:

x = 28

So, the length of side BC is 28 meters, and the length of side CA is also 28 meters.

The length of the base AB is (x + 7) = (28 + 7) = 35 meters.

Therefore, the sides of the triangle ABC are: - BC = 28 meters - CA = 28 meters - AB = 35 meters

Answer

The lengths of the sides of the triangle ABC are: - BC = 28 meters - CA = 28 meters - AB = 35 meters

I hope this helps! Let me know if you have any further questions.