Question

В ромбе ABCD проведена диогональ AC,найдите угол ABC, если известно что, угол ACD= 20 ГР.

Answer 1

Если угол асд=20гр, то угол всд= 20*2=40гр
а так как сумма углов авс и всд = 180 (по свойству ромба), то угол авс=180-40=140гр

Answer 2

Finding the Angle ABC in a Rhombus

To find the angle ABC in a rhombus ABCD, where a diagonal AC is known to have an angle ACD of 20 degrees, we can use the properties of a rhombus.

A rhombus is a quadrilateral with all four sides of equal length. It also has some other properties, such as opposite angles being equal and diagonals bisecting each other at right angles.

Let's proceed with finding the angle ABC step by step:

1. We know that the angle ACD is 20 degrees. 2. Since ABCD is a rhombus, opposite angles are equal. Therefore, angle BCD is also 20 degrees. 3. The sum of the angles in a quadrilateral is 360 degrees. So, angle ABC can be found by subtracting the sum of the known angles (ACD and BCD) from 360 degrees. - Angle ABC = 360 degrees - (angle ACD + angle BCD) - Angle ABC = 360 degrees - (20 degrees + 20 degrees) - Angle ABC = 360 degrees - 40 degrees - Angle ABC = 320 degrees.

Therefore, the angle ABC in the rhombus ABCD is 320 degrees.

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